SQLException: Before start of result set
Today I was getting this error when making a SELECT query. This error is raised typically because you didn't call resultset.first() or resultset.next() function.
So before using a field from a record in MySQL
if ( Portal != null && Portal.next() ){
url = "//"+Portal.getString("portal_url")+".domain.com/"+ RS.getString("permalink");
}
1 Comments:
This comment has been removed by the author.
Post a Comment
<< Home